LAWS OF EXPONENTS
The following laws of exponents are for multiplying and dividing monomials.
PRODUCT RULE:
am · an = am+n (when multiplying like bases, add the powers)
Examples:
1) x4 · x5 = x4+5 = x9 2) 55 · 58 = 55+8 = 513
3) a7 · a · a12 = a7+1+12 = a20 4) (3x6)(2x4) = (3·2)x6+4= 6x10
5) (4m8n2)(-2mn4)(5m4n3) = (4·-2·5)(m8+1+4)(n2+4+3) = -40m13n9
POWER RULE:
(ambm)n
= amnbmn
(when taking a monomial to a power, multiply the powers including
the coefficient)
Examples:
1) (a4b3)2 = a8b6 2) (3m2n5)4 = 34m8n20 = 81m8n20
3) (-2xy7z2)5 = (-2)5x5y35z10 = -32x5y35z10
4) (6a9b6)2
= 62a18b12
= 36a18b12
(-c4d2)5 (-1)5c20d10
-c20d10
QUOTIENT RULE:
am = am -
n (when dividing with like bases, subtract the
powers)
an
(Note: it is
always the numerator's power minus the denominator's power)
Examples:
1) x6 = x6 – 4 = x2 2) m5n7 = m5-4n7-10 = mn-3
x 4 m4n10
3) a3b7 = a3 - (-5)b7-9 = a8n-2
a-5b9
ZERO POWER RULE:
a0 = 1 (any term to the zero power is one)
Examples:
1) (m5 n7)0 = 1 2) (4m8n2)(-2mn4)0 = (4m8n2)(1) = 4m8n2
****It is improper to leave negative powers in your final answer. All final answers should be written with positive powers. Therefore, you will need the following property. ****
NEGATIVE POWER RULE:
a-n = 1 and 1 = an (take the reciprocal of the variable to the negative power)
an a-n
Examples:
1) 3x-4 = 3 · 1 = 3 2) -5m-8n2 = -5y5n2 x4 x4 x10y-5 m8x10
NOTE: Apply the negative power rule to only negative POWERS.
EXAMPLES: Simplify the following expressions. Write the final answers without negative exponents.
Simplify means to combine like terms using the laws of exponents. Also, you may work with negative powers as you are simplifying within the problem. You just cannot leave negative powers in the final answer.
1) 12-4(128) = 12-4+8 =124 (product rule)
or = 1 •128 (negative power rule)
124
= 128 - 4 = 124 (quotient rule)
2) (5a4b6)(12abc)0(-2a2bc5)
= (5a4b6) (1) (-2a2bc5)
(zero power rule)
-10a6b7c5
(product rule)
3) -42m6n-3p5 = -7m6-11 n-3-(-5) p5-5 (quotient rule)
6m11n-5p5
= -7m-5n2p0
= -7n2
(negative power and zero power
rule)
m5
4) (-3ab6 )5 = (-3)5a5b30 (power rule)
(-a5b2)7 (-1)7a35b14
= -243a5b30
-1a35b14
= 243a5-35b30-14 (quotient rule)
= 243a-30b16
= 243b16
(negative power rule)
a30
5) 2m7n3 • (3mp8)3 = 2m7n3 • 27m3p24 (power rule)
(3n5p-3)2 2mn6 9n5p-6 2mn6
= 54m10n3p24 (product rule)
18mn11p-6
= 3 m10-1n3-11 p24 - (-6) (quotient rule)
= 3m9n-8p30
= 3m9p30 (negative power rule)
n8
6) (7xy)(-x4y3)5(2x5y6)-2 = (7xy)(-15x20y15)(2-2x -10y -12) (power rule)
= (7xy)(-x20y15)(x
-10y -12)
(negative power
rule)
22
= -7 x1+20-10 y1+15-12 (product rule)
4
= -7 x11
y4
4
7) (2)-5 = (need to apply the negative power rule first before you can multiply)
= or
= is the final answer.
8) = ÷ (quotient rule)
= 510 ÷ 5-13
= 510-(-13) (quotient rule)
= 523
9) = (power rule)
=
= = (product rule)
= x12m + 12 – (8m – 6 ) = x12m + 12 – 8m + 6 (quotient rule)
= x4m + 18
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